Which is faster - inserting an element at the end of an array or a linked list
Which is faster - inserting an element at the end of an array or a linkedlist ?
I assume you meant ArrayList when you said "array", since in Java you can't "add" to a full array. Firstly if you're "inserting at the end" you're actually appending to the end not, "inserting". This distinction is important because inserting into an ArrayList at an arbitrary position is an O(n) operation, because all elements to the right must be "shifted" along by one position to make room for the element being inserted. Adding to (the tail of) a LinkedList is always a O(1) (constant time) operation. Adding to an ArrayList is usually a O(1) operation, but may be a O(n) operation if the backing array is full, because a new array must be allocated and every element copied across. In the general case of the array not being full, the performance of ArrayList is (slightly) faster than LinkedList, but the difference is very small. The amortised cost of both is the same, but if constant time is required every time, only a LinkedList can do it.
Appending an element to the end of Array would be faster then Adding to a LinkedList as adding to a LinkedList always means creation of a cell at the end of the list and then adding a value to it. In Array you just add a value to existing cell. However, in Array if it is already full and doesn't have a space you will get IndexOutOfBoundsException while in the LinkedList you will never have this problem as the List will always grow according to your needs. Also there is distinct difference between LinkedList and ArrayList with ArrayList there is a random access which means the access to any element is always O(1) while in LinkedListit is always sequential access which means that access time will differ depending on the index and in worst case scenario is O(n). However, Appending to LinkedList is Always O(1) but not so in ArrayList With ArrayList if it is not full it will be O(1) but if it is full it will first grow by more then one cell and only ten it will add the value, so the worst case scenario is O(n)
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